one ticket is selected at random from 100 tickets numbered 00,01,02,.......,99. suppose X is sum and Y is the product of the digit found on the ticket, P(X=9/Y=0) is given by....
Experts I want the answer in detailed steps, so that I can understand it better..
The link you sent me for the last time did not have the detailed steps.
product of the digit found on the ticket = 0 ,
therefore one digit must be 0.
therefore possible outcomes = {00,01,02,03,04,05,06,07,08,09,10,20,30,40,50,60,70,80,90}
total number of outcomes = 19
and the sum of the digits = 9
since one digit is 0 , therefore other digit must be 9.
thus the possible number on the ticket is 09 or 90
number of favorable outcomes = 2
thus the required probability = 2/19
hope this helps you
therefore one digit must be 0.
therefore possible outcomes = {00,01,02,03,04,05,06,07,08,09,10,20,30,40,50,60,70,80,90}
total number of outcomes = 19
and the sum of the digits = 9
since one digit is 0 , therefore other digit must be 9.
thus the possible number on the ticket is 09 or 90
number of favorable outcomes = 2
thus the required probability = 2/19
hope this helps you