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Out of the families having 3 children,a family is chosen random.Find the probability that the family has (a) at most one girl...

A family has three children.

Total outcomes = GGG , GGB ,GBG ,BGG, BBB ,BBG, BGB ,GBB = 8

At most one girl mean no girl or 1 girl

So, favourable outcomes = BBB, BBG, BGB, GBB = 4

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N(s) = GGG , GGB ,GBG ,BGG, BBB ,BBG, BGB ,GBB

N(s) =8

at one girl mean  1 girl or more.

therefore , P(g) = 7/8

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ANSWER IS 1/2

TOTAL OUTCOMES ARE 8.

BBB ,BBG, BGB, BGG ,GBB, GBG, GGB ,GGG.

OUT OF WHICH ONLY 4 HAVING ATMOST ONE GIRL.

BBB,BBG,BGB,GBB HENCE PROBABILITY IS 4/8 OR 1/2

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ATMOST MEANS 1GIRL OR LESS GIRL OR NO GILRS

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