Particle A makes a perfectly elastic collision with another particle B at rest. They fly apart in opposite direction with equal speeds.. If their masses are mA & mB respectively, then:- a) 2mA=mB b) 3mA=mB c) 4mA=mB d) (3)1/ 2mA=mB Share with your friends Share 91 Govind answered this Givenm1=mA, m2=mB, u1=u, u2=0Applying principle of conservation of kinetic energym1u+0=m1v+m2-v=m1-m2v .....1 ⇒uv=m1-m2m1 .....2From the principle of conservation of energy, we have12m1u2=12m1+m2v2 .....3Dividing 3 by 1, we getuv=m1+m2m1-m2 .....4Comparing equation 2 and 4, we havem1+m2m1-m2=m1-m2m1On solving we getm1m2=13 or mAmB=13 174 View Full Answer