pl can some one differentiate y=log(x+(x^2+a^2)^1/2) Share with your friends Share 1 Kuldeep answered this =1/X+ (x2 + a2 )1/2 d/dx( X+ (x2 + a2 )1/2 )=1+ X / (X2 + a2 ) 1 View Full Answer Satwik answered this Y= log[x+(x2+a2)1/2] Y'= 1/(x2+a2)1/2 0
