2/9 i guess. May be wrong. I just found the lines' intersection point, hence the perpendicular distance between that point and y axis and then multiplied it by the distance between the y-intercepts of the lines. And halved that(area of a triangle formula. You can also find the lines' intersection point, and y intercepts, and put those values in the area of a triangle formula of co-ordinate geometry (1/2| x1(y2-y3) + x2(y3-y1) + x3(y1-y2) | ). Again, It may be wrong
Regards