Pl solve this question 4

D e a r S t u d e n t, G i v e n, R_{1} = 37 Ω, R_{2} = 54 Ω, Δ R_{1} = \pm 3 Ω, Δ R_{2} = \pm 5 Ω F o r a s e r i e s c o n n e c t i o n e q u i v a l e n t r e s i s \tan c e i s, R_{e q} = R_{1} + R_{2} + Δ R_{1} + Δ R_{2} \Rightarrow R_{e q} = (37 + 54) (\pm 3 \pm 5) = (91 \pm 8) Ω R e g a r d s .