Please answer 1 and 4 and tell if 2 and 3 answer is correct experts
Please find below the answer:
The woman must be a carrier, as her father was colour-blind.
XcX (Carrier female) x XCY (colour-blind male)
Offspring X C X C X C Y XXC XY
(1) (2) (3) (4)
1- Affected female.
2- Affected male.
3- Normal female.
4- Normal male.
Baldness is an autosomal trait. A man needs only one allele (B) for the baldness trait to be expressed, while a bald woman must be homozygous for the trait (BB). If B is the allele for baldness and b is the allele for normal hair, a bald man can be heterozygous (Bb) or homozygous bald (BB). A man with normal hair must be homozygous normal (bb). A normal woman can be homozygous normal (bb) or heterozygous (Bb).
Since the man is bald, he can have either BB or Bb genes and since the woman's mother was bald, she can have BB, Bb or bb. To find out the probability of bald offspring is not possible here because the woman's father's phenotype is not known.
Regards.