Please answer 18th question:

Let r be the radius of the base and h be the height of the cylinder . Now, volume = 3960 \Rightarrow {πr}^{2} h = 3960 . . . . . . (1) CSA = 1320 {cm}^{2} \Rightarrow 2 πrh = 1320 . . . . . . . (2) Dividing (1) by (2), we get \frac{{πr}^{2} h}{2 πrh} = \frac{3960}{1320} \Rightarrow r = 6 cm Now, from (2), we get 2 \times \frac{22}{7} \times 6 \times h = 1320 \Rightarrow h = \frac{1320 \times 7}{44 \times 6} = 35 cm

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