Please answer 3 question immediately 3 Find the value of 243n5 × 32n+19n + 3n-1 - Maths - Exponents and Powers

Question

Please answer 3 question immediately

3       F i n d   t h e   v a l u e  
o f   243 n 5   ×   3 2 n + 1 9 n   +
  3 n - 1

Shruti Tyagi · Accepted Answer

Dear student,

We have,243n5×32n+19n+3n-1=35n5×32n+132n+3n-1=3n×32n+132n+3n-1                   
[as amn=amn]=3n+2n+132n+n-1                   
[as am×an=am+n]=33n+133n-1=33n+1-3n-1                
[as am÷an=am-n]=33n+1-3n+1=32=9

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Please answer 3 question immediately 3 . F i n d t h e v a l u e o f 243 n 5 × 3 2 n + 1 9 n + 3 n - 1 .

Please answer 3 question immediately

$3 . F i n d t h e v a l u e o f \frac{{(243)}^{\frac{n}{5}} \times 3^{2 n + 1}}{9^{n} + 3^{n - 1}} .$