Please answer again by using 5 co-efficients, "a,b,c,d,e"           without changing anything, {don't change a single numeral too}  in the given equation. 


Question 1 for today:
Balance the below chemical equation by using Algebraic method only. Also show the process. 
​$\mathit{Q}\mathbf{.} Cu + HN{O}_3 \to Cu{\left(N{O}_3\right)}_2 + NO + H_{2}O$
{Please don't solve this using any other method and don't provide similar questions.}​​

Given:

Cu + HNO₃ ---> Cu(NO₃)₂ + H₂O + N₂O

Keep in mind: oxidation no. of Cu = +2 , NO₃ = -1, 

i.e. for formation of Cu(NO₃)₂ we need 2 moles of HNO₃

Reaction becomes, 

Cu + 2HNO₃ ---> Cu(NO₃)₂ + 2H

However there is formation of N2O and H2O i.e we have to consider 2N and 2 O

They have to come from HNO₃ we need to add 2 moles.

therefore reaction becomes,

Cu + 4HNO₃ ---> Cu(NO₃)₂ + 2H₂O + N2O + 3O 

there are 3 unaccounted O atoms, now it should be remembered that  oxygen will prefer to react with H to form H₂O than form N₂O

hence we need 6 H atoms, which will come from 6 HNO3, molecules

Cu + 10HNO₃ ---> Cu(NO₃)₂ + 5H₂O + N₂O + 6 (NO ₃ )^-

 The unaccounted NO₃ ^- ions may be accounted by adding 1 Cu atom per 2 NO₃ ^-  ion

Now, the reaction becomes,

4Cu + 10HNO ₃ ---> 4Cu(NO ₃ ) ₂ + 5H ₂ O + N ₂ O

 This is the balanced reaction.

You will study this in your higher grades.

Regards