Please answer as soon as can Share with your friends Share 0 Vartika Jain answered this Dear Student, BaCl2 + Na2SO4 → BaSO4 + 2NaCl1 mol 1 mol 1 molNow, Moles of BaCl2= Molarity×Volume= 0.2 M×0.5 L=0.1 molMoles of Na2SO4 = Molarity×Volume= 0.15 M×0.4 L=0.55 molNow, for the formation of 1 mol of BaSO4, 1 mol of BaCl2 and 1 mol of Na2SO4 are requiredBut, moles of BaCl2 is less than Na2SO4 , which makes it the limiting reagent. Now, 1 mol of BaCl2 gives 1 mol of BaSO4So, 0.1 mol of BaCl2 will give 1×0.1 =0.1 mol of BaSO4Mass= No. of moles×Molar massMolar mass of BaSO4= 137+32+4×16=233 g mol-1Therefore, mass= 0.1 mol×233 g mol-1=23.3 g -1 View Full Answer
