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Dear Student
Given A.P {1,4,7.....}
1st term, a=1
Common difference,d=4-1=3
nth term=[a+(n-1)d]={1+3(n-1)}=(3n-2)
Sum of nth term=[n/2{2a+(n-1)d}]
Regards
Given A.P {1,4,7.....}
1st term, a=1
Common difference,d=4-1=3
nth term=[a+(n-1)d]={1+3(n-1)}=(3n-2)
Sum of nth term=[n/2{2a+(n-1)d}]
Regards