Dear Student,

Please find below the solution to the asked query:

1) Calculate the cell constant, K:

K = specific conductivity (κ) x Resistance (R) = (1.29 x 10-2 ohm-1 cm-1) x (85 ohm) = 1.0965 cm-1

2) Using this cell constant calculate the specific conductivity of the electrolyte at 0.052 M concentration.

specific conductivity (κ) = K / R = 1.0965 cm-1 / 96 ohm = 1.14 x 10-2 ohm-1 cm-1

3) Molar conductivity = Specific conductivity (ohm-1 cm-1)concentration (mol L-1)×1000 (cm3 L-1)= 1.14×10-2 ohm-1 cm-10.052 mol L-1×1000 (cm3 L-1= 219 ohm-1 cm2 mol-1

Hence, the molar conductivity of the unknown electrolyte at 0.052 M is 219 ohm-1 cm2 mol-1.

Hope this information will clear your doubts about Electrochemistry.
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