ocal length, f=15cm

Object distance, u=25cm

Object height, h0​=4cm

From mirror formula,

f1​=v1​+u1​

−151​=−251​+v1​

⇒v1​=−151​+251​

v=−37.5cm

magnification, m=−uv​=h0​hi​​

⇒m=−−25(−37.5)​=4hi​​

hi​=−2537.5×4​

hi​=−6cm

To get a sharp image, v=37.5cm
The image is real, inverted and magnified
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SIMILAR QUESTIONS

Plot the image of an object in an optical system consisting of a convergent lens and a flat mirror arranged in the focal plane of the lens . The object is infront of the lens and between the focus and the double focal length of the lens . What will be the size of the image if the object is positioned arbitrarily ?

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An object 4.0 cm in size, is placed 25.0 cm in front o