please answer it fast

Dear student,

$$\begin{gathered} We know that, \\ Area of rt ∆ = \frac{1}{2}\times base\times height \\ then Area of rt ∆ABC=\frac{1}{2}\times BC\times AD \\ =\frac{1}{2}\times 5.5\times 4 \\ =5.5\times 2 \\ =11 c{m}^2 \end{gathered}$$
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