Please answer my question (4)? Share with your friends Share 0 Atul Shaw answered this Dear student, Given length of common chord AB=12 cmLet the radius of the circle with centre O is OA=10 cmRadius of circle with centre P is AP=8 cmFrom the figure, OP⊥AB⇒AC=CB∴AC=6 cm (Since AB=12 cm)In ΔACP,AP2=PC2+AC2 [By Pythagoras theorem]⇒82=PC2+62⇒PC2=64–36=28PC=2 7 cmConsider ΔACO,AO2=OC2+AC2 [By Pythagoras theorem]⇒102=OC2+62⇒OC2=100−36=64 ⇒OC=8 cmFrom the figure, OP=OC+PC=8+27 cmHence, the distance between the centres is (8+27 ) cm.Regards 0 View Full Answer