Please answer my question (81)?
Dear Student,
During neutralization of NaOH with HCl, gram equivalents of acid = base.
No. of gram equivalents = Normality x Volume
NaOH = 0.4 N, V ml
HCl = 0.2 N, 200 ml
NNaOHVNaOH = NHClVHCl
0.4 x V = 0.2 x 200
VHCl = 100 ml
Regards
During neutralization of NaOH with HCl, gram equivalents of acid = base.
No. of gram equivalents = Normality x Volume
NaOH = 0.4 N, V ml
HCl = 0.2 N, 200 ml
NNaOHVNaOH = NHClVHCl
0.4 x V = 0.2 x 200
VHCl = 100 ml
Regards