Please answer my question (81)?

Dear Student,
During neutralization of NaOH with HCl, gram equivalents of acid = base.

No. of gram equivalents = Normality x Volume
NaOH = 0.4 N, V ml 
HCl = 0.2 N, 200 ml 

     NNaOHVNaOH = NHClVHCl 
0.4 x V = 0.2 x 200
VHCl = 100 ml

Regards

 

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