Please answer my question experts

Dear Student,



So, ferquency % cross over as per the formula:
= 26+24/124+126+26+24
= 50/300
= 16.67%
Total frequency of cross ove is ~17%
frequency of indivisual cross over:
26/300= 8.6% for ab/ab
24/300= 8% for ++/ab

Now distance between the 2 linke gene= 100 x % frequency cross over
i.e. 100 x 16.67 % = 16.67 cM
(# cM or centi Morgan is the unit of distance between linked genes)

Regards,
​​​​​
​​​​