Please answer Q.2 as soon as possible Share with your friends Share 0 Rohit Babu answered this Dear Student,Let u be the initial velocity and a be the acceleration,Body travels 84 m in first 6 seconds.Therefore,84=6u+12a×3684=6u+18a14=u+3a.............(1)In the next 5 seconds it travels 264mt=6+5=11sec264=11u+12a×121528=22u+121a........(2)(1)×22⇒308=22u+66a.......(3)(2)-(3)220=0+55aa=22055=4 m/s2Sub value of a in (1)14=u+12u=2m/sRegards.. 0 View Full Answer
