Dear student The system AX=B of n equations in n unknowns has infinitely many solutions ifdetA=0 and adjAB=0We have,AX=B, where A=0⇒adj A(AX)=adj AB⇒adj AAX=(adj A)B⇒AInX=(adj A)B⇒AX=adj AB⇒A=0 and adj AB=0, then AX=adj ABis true for every value of X So, the system of equations AX=B has infinitely many solutions Regards

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please answer Question 12 of 90 The system AX = 8 of n equations in n unknowns has infinitely many solutions if 2. 3. 4. O O O O det 0 det A- O, (adjA)B det A- O, (adjA)8 = O detA (adjA)8 = O

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The system AX = B of n equations in n unknowns has infinitely many solutions if detA = 0 and (adjA) B = 0 We have, AX = B, where |A| = 0 \Rightarrow (adj A) (AX) = (adj A) B \Rightarrow ((adj A) A) X = (adj A) B \Rightarrow (|A| I_{n}) X = (adj A) B \Rightarrow |A| X = (adj A) B \Rightarrow |A| = 0 and (adj A) B = 0, then |A| X = (adj A) B is true for every value of X . So, the system of equations AX = B has infinitely many solutions .

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​please answer​please answer Question 12 of 90 The system AX = 8 of n equations in n unknowns has infinitely many solutions if 2. 3. 4. O O O O det 0 det A- O, (adjA)B det A- O, (adjA)8 = O detA (adjA)8 = O

please answer
please answer Question 12 of 90 The system AX = 8 of n equations in n unknowns has infinitely many solutions if 2. 3. 4. O O O O det 0 det A- O, (adjA)B det A- O, (adjA)8 = O detA (adjA)8 = O