Please answer question 16

Please answer question 16 16. For a capacitor the distance between two plates is 5* and the electric field between them is Ea. Now a dielectric slab having dielectric constant 3 and thickness x is placed between them in contact with one plate. In this condition what is the p.d. between its two plates? (c) 7Eox 9Eox 17. The distance between electric charges 1 C and 9 C is 4 m. Whatis the electric potential ata point on the line joining them where the electric field is zero ? (d) 22.5 x 109v x 109 v (a)90 10' V (b) 36 x IOAv 18. Ten identical square metallic plates are arranged as in figure. Length of each plate is The capacitance of this arrangement would be (a) 6d 19. In a certain region the electric potential is given bv the formula 3ya — 4z'x . Find the Z - component of the electric field at the point in this field. (b) 11 unit (a) —11 unit (c) 13 unit (d) O unit 20. A slab of copper ofthickness 'b' is inserted in between the plates of parallel plate capacitor as shown in figure. The separation between the plates is 'd'. if b d/2, then the ratio of capacitance of capacitor before and aft r inserting the slab will be PART -B

Dear student,
The potential difference is given by the formula,

V = E_{0} (d - t + t / k) h e r e d = 5 x, t = x a n d k = 3 s o V = E_{0} (5 x - x + x / 3) = 13 E_{0} x / 3

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