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Dear student, (2 + \sqrt{3}) (2 - \sqrt{3}) = 2^{2} - {(\sqrt{3})}^{2} = 4 - 3 = 1 \frac{\sqrt{3}}{\sqrt{5} + \sqrt{2}} \times \frac{\sqrt{5} - \sqrt{2}}{\sqrt{5} - \sqrt{2}} = \frac{\sqrt{3} (\sqrt{5} - \sqrt{2})}{{(\sqrt{5})}^{2} - {(\sqrt{2})}^{2}} = \frac{\sqrt{3} (\sqrt{5} - \sqrt{2})}{5 - 4} = \sqrt{3} (\sqrt{5} - \sqrt{2}) = \sqrt{15} - \sqrt{6} (a + b) (a - b) = a^{2} - b^{2} Regards

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