Please answer the following question. As soon as possible.
The options are
a) 24 N b) 28 N c) 32 N d) 10 N
Dear Student
Momentum of one bullet, p = mv
p = 20 × 10−3 × 300 = 6 kg m s−1
N = number of bullet per sec = 4
So in one second momentum = Np
∴dp// dt = change of momentum per sec or force
= N(p - 0) = 4 × 6 = 24 N
Regards
Momentum of one bullet, p = mv
p = 20 × 10−3 × 300 = 6 kg m s−1
N = number of bullet per sec = 4
So in one second momentum = Np
∴dp// dt = change of momentum per sec or force
= N(p - 0) = 4 × 6 = 24 N
Regards