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Dear student,f(x) = x3-5x2+6x-4q(x) = x-3  r(x) = -3x+5  g(x) = ?  Now,  f(x) = g(x).q(x)+r(x)  So, g(x) = f(x)-r(x)q(x)    g(x) = (x3-5x2+6x-4)-(-3x+5) x-3  g(x) = x3-5x2+9x-9x-3   g(x) = x2(x-3)-2x(x-3)+3(x-3)(x-3)Therefore, g(x)=x2-2x+3Regards

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