Please answer the question

Dear Student,

let us consider a string consist of a stone of mass m revolving in a horizontal circle with constant speed v at the end of a string of length l . Let the string makes a constant angle θ with the vertical . Let h be the depth of the stone below the support . from figure, F cosθ = mg . . . . . . (1) F sinθ = \frac{{mv}^{2}}{r} . . . . . (2) divide equation (2) by (1) \frac{F sinθ}{F cosθ} = \frac{\frac{{mv}^{2}}{r}}{mg} tanθ = \frac{v^{2}}{rg} v^{2} = rg tanθ Also, v = rω r^{2} ω^{2} = rg tanθ Also, from figure tanθ = \frac{r}{h} r^{2} ω^{2} = rg \times \frac{r}{h} ω^{2} = \frac{g}{h} From figure, h = l cosθ ω^{2} = \frac{g}{l cosθ} cosθ = \frac{g}{{lω}^{2}} θ = \cos^{- 1} (\frac{g}{{lω}^{2}})

Regards