Please answer the question Share with your friends Share 0 Varun Rawat answered this Dear Student, Since, AB∥DC and ED is a transversal, then∠AED = ∠EDC alternate interior angles .....1Since, ED bisects ∠ADC, then∠EDC = ∠ADE ......2From 1 and 2, ∠AED = ∠ADEIn ∆ADE, ∠AED = ∠ADE proved above⇒AD = AE Sides opposite to equal angles are equal .......3Since, AB∥DC and EC is a transversal, then∠BEC = ∠ECD alternate interior angles .....4Since, EC bisects ∠BCD, then∠ECD = ∠ECB ......5From 4 and 5, ∠BEC = ∠ECBIn ∆EBC, ∠BEC = ∠ECB proved above⇒BC = EB Sides opposite to equal angles are equal .......6Now, AB = AE + EB = AD + BC Using 5 and 6 Regards 0 View Full Answer
