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D e a r S t u d e n t, G i v e n, F = 10 N, m = 2 k g, θ = 60^{0}, s = 2 m C o m p o n e n t o f f o r c e a l o n g h o r i z o n t a l d i r e c t i o n i s, F_{H} = F \cos θ = 10 \cos 60^{0} = 5 N T h e r e f o r e, K . E = W o r k d o n e = F_{H} s = 5 \times 2 = 10 J R e g a r d s . . .

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