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The given equations are : 2 x + 3 y - 5 = 0 kx - 6 y - 8 = 0 Comparing the above equations with a_{1} x + b_{1} y + c_{1} = 0 and a_{2} x + b_{2} y + c_{2} = 0, we get a_{1} = 2; b_{1} = 3; c_{1} = - 5 a_{2} = k; b_{2} = - 6; c_{2} = - 8 For unique solution : \frac{a_{1}}{a_{2}} \neq \frac{b_{1}}{b_{2}} \Rightarrow \frac{2}{k} \neq \frac{3}{- 6} \Rightarrow k \neq - 4 The above system of equations has unique solution for all the real values of k except - 4 .

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