# Please answer this fast....

Dear student,

Mass of the Sun, *M* = 2.0 × 10^{30} kg

Radius of the Sun, *R* = 7.0 × 10^{8} m

Volume of the Sun, *V* = $\frac{4\pi {R}^{3}}{3}$

$=\frac{4}{3}\times \frac{22}{7}\times {(7\times {10}^{8})}^{3}\phantom{\rule{0ex}{0ex}}=\frac{88}{21}\times 343\times {10}^{24}=1437.3\times {10}^{24}{m}^{3}$

Density of the Sun = $\frac{mass}{volume}=\frac{2\times {10}^{30}}{1437.3\times {10}^{24}}=1.4\times {10}^{3}kg/{m}^{3}$

The density of the Sun is in the density range of solids and liquids. This high density is attributed to the intense gravitational attraction of the inner layers on the outer layer of the Sun.

Regards

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