Please answer this query as fast as possible and please dont answer in links solve the answer. Share with your friends Share 0 Neha Sethi answered this Dear student Given:5sinθ+3cosθ=4 ...1To find: 3sinθ-5cosθConsider, 5sinθ+3cosθ2+3sinθ-5cosθ2=25sin2θ+9cos2θ+30sinθcosθ+9sin2θ+25cos2θ-30sinθcosθ=34sin2θ+34cos2θ=34sin2θ+cos2θ As sin2θ+cos2θ =1=34⇒5sinθ+3cosθ2+3sinθ-5cosθ2=34⇒42+3sinθ-5cosθ2=34 using 1⇒3sinθ-5cosθ2=34-16⇒3sinθ-5cosθ2=18⇒3sinθ-5cosθ=±32 Regards 1 View Full Answer Sheeba Lidwin answered this what query ???? 0 R. Lasyapriya answered this THIS THE QUES 33.> PLEASE ANSWER AS FAST AS POSSIBLE 0