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Dear student
Given:5sinθ+3cosθ=4  ...1To find: 3sinθ-5cosθConsider, 5sinθ+3cosθ2+3sinθ-5cosθ2=25sin2θ+9cos2θ+30sinθcosθ+9sin2θ+25cos2θ-30sinθcosθ=34sin2θ+34cos2θ=34sin2θ+cos2θ   As sin2θ+cos2θ =1=345sinθ+3cosθ2+3sinθ-5cosθ2=3442+3sinθ-5cosθ2=34   using 13sinθ-5cosθ2=34-163sinθ-5cosθ2=183sinθ-5cosθ=±32
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THIS THE QUES 33.> PLEASE ANSWER AS FAST AS POSSIBLE

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