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W i t h o u t   u sin g   t r i g o n o m e t r i c
  t a b l e s ,   e v a l u a t e 2 cos   58 °
sin   32 °   -   3   cos   38 °
  cos e c     52 ° tan   15 °  
tan   60 °   tan   75 °

Neha Sethi · Accepted Answer

Dear student
2 cos58°sin32°-3cos38° cosec52°tan15° tan60° tan75°=2cos58°sin90°-58°-3 cos38° cosec90°-38°tan15° tan60° tan90°-15°=2 cos58°cos58°-3 cos38° sec38°tan15° tan60° cot15°=2-3tan60°    =2-33=2-1=1
Note:
sin90°-x=cosxcosec90°-x=secxtan90°-x=cotx

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Please answer this question. Please do not send any links. W i t h o u t u sin g t r i g o n o m e t r i c t a b l e s , e v a l u a t e 2 cos 58 ° sin 32 ° - 3 cos 38 ° cos e c 52 ° tan 15 ° tan 60 ° tan 75 °

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$W i t h o u t u \sin g t r i g o n o m e t r i c t a b l e s, e v a l u a t e 2 (\frac{\cos 58 °}{\sin 32 °}) - \sqrt{3} (\frac{\cos 38 ° \cos e c 52 °}{\tan 15 ° \tan 60 ° \tan 75 °})$