# Please answer this question ....the answer as given in the book is the (e) part

Here we can see that both the reactions:

A > B, k

_{1}= 12.6 x 10

^{-4}

A > C , k

_{2}= 3.8 x 10

^{-4}(It should be -4, not -5, it is a misprint.)

are 1st order. So, if both of these proceed simultaneously, then, there must be a ratio between the rate constants.

So, $\frac{{k}_{1}}{{k}_{2}}=\frac{12.6\times {10}^{-4}}{3.8\times {10}^{-4}}=3.3158$

Converting this to percentage, we have, k

_{2}= 23.17% and k

_{1}= 23.17 x 3.3158 = 76.83%

Regards

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