Please answer this question tomorrow exams
The mass percentage of a solution is defined as
Where, mass of a solution = Mass of solute + Mass of solvent
We are given that the sugar solution is 2.5 % and the mass of solution is 500g. Let y grams be the mass of sugar (solute) present in 500g of solution. Therefore
2.5 = (y / 500) X 100
This gives y = 12.5
Therefore mass of water (solute) = mass of solution - mass of sugar (solute)
= (500 - 12.5) g
= 487.5 g
Hence 487.5 g of water would be required.
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