Please answer this question..... very urgent.

​Q17. In the figure below, AL is perpendicular to BC and CM is perpendicular to AB. If CL = AL = 28 L, find MC/ AM 

     (A) 2                          (B) 3                    (C) 4                        (D) Cannot be determined

Dear student

Let BL=1Then CL=AL=2   AL=CL=2BLIn ALB by pythagoras theorem.AB=AL2+BL2=22+12=5and In ALC by pythagoras theorem.AC=AL2+CL2=22+22=8=22Let AM=x.ThenIn AMC by pythagoras theorem.CM=AC2-AM2=222-x2=8-x2In ALB and MCBALB=CMB    [each 90°]B=B   [Common]So, ALB~CMB   [By AA criteria]So, ALCM=LBMB=ABCBALCM=ABCBAB×CM=CB×AL5×8-x2=3×258-x2=368-x2=3658-x2=7.2x2=0.8So, MCAM=8-x2x=8-0.80.8=7.20.8=9=3
Regards

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