Please answer with detail all the questions within 10 hours.:


1.  If   1 log 2 π + 1 log 4 π > k   than   the   value   of   k   is   where   k   is   any   integer . ( A )   1                         ( B )   2                         ( C ) 3                     ( D )   4 2 .   If   log 4 5 = x   and   log 5 6 = y ,   then .   ( A )   log 4 6 = xy ,       ( B )   log 6 4 = xy               ( C )   log 3 2 = 1 2 xy - 1     ( D )   log 2 3 = 1 2 xy - 1

Dear student
2.Given: log4 5=x and log5 6=yNow,x×y=log4 5× log5 6xy=log5log4×log6log5    Since logab=logblogaxy=log6log4xy=log46xy=log226xy=12log26      Since loganb=1nlogabxy=12log22×3xy=12log22+log23      Since logabc=logab+logac2xy=1+log23log23=2xy-1log32=12xy-1So, correct option is C.
For remaining queries we request you to post them in separate threads to have rapid assistance from our experts.
​Regards

  • 0
What are you looking for?