Dear Student, A+ + B- → A2+ + B2-∆G1=-nFEHere, n=1So, x=-FE (i)Similarly,12A+ + 12B- →12 A2+ + 12B2-n=12∆G2=-nFEHere, n=12So, ∆G2= -12FE (ii)Sividing (i) and (ii)x∆G2=-FE-FE2ot, ∆G2=x2Hence, the correct answer is (1)

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A^{+} + B^{-} \to A^{2 +} + B^{2 -} ∆ G_{1} = - nFE Here, n = 1 So, x = - FE . . (i) Similarly, \frac{1}{2} A^{+} + \frac{1}{2} B^{-} \to \frac{1}{2} A^{2 +} + \frac{1}{2} B^{2 -} n = \frac{1}{2} ∆ G_{2} = - nFE Here, n = \frac{1}{2} So, ∆ G_{2} = - \frac{1}{2} FE . . (ii) Sividing (i) and (ii) \frac{x}{∆ G_{2}} = \frac{- FE}{\frac{- FE}{2}} ot, ∆ G_{2} = \frac{x}{2} Hence, the correct answer is (1)

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