Please anyone answer it full please

Dear student,

Q1) As given In period 2 the element A is to the right of element B, it means when we move across the period from left to right element B will come first and then element A will come.
1) The element A would probably have a smaller atomic size than B.
 Reason: The atomic size decreases as we move across the period from left to right.
2) The element B would probably have lower Ionization potential than A.
Reason: The ionization potential increases as we move across the period from left to right.
3) The element A would have higher electron affinity than B.
Reason: The electron affinity increases on moving from left to right across the period in aperiodic table.
4) Nuclear charge of B would be less than element A.
5) If an element C had a low electronegativity and ionization potential it would have more tendency to lose electrons.
Reason: Lower is the electronegativity lower will be the tendency to gain electrons means higher tendency to lose electrons and an element having low ionization potential will easily lose electrons.

Please ask the remaining queries in next thread.

Regards

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