Please anyone solve it and explain - Chemistry - Mole Concept and Stoichiometry

Question

Please anyone solve it and explain

Utkarsh Pathak · Accepted Answer

Dear Student,

Element
AtomicMass
Percentage
Relative Number of Moles
Simplest mole of Ratio
Whole Number ratio

Pb(Lead)
207
90 66%
90 66/207=0 44
0 44/0 44=1
1X3=3

O(oxygen)
16
9 34%
9 34/16=0 58
0 58/0 44=1 318
1 32X3=3 96

Since, the mole ratio of oxygen
is fractional so, we multiply the whole ratio by 3 to make it a
whole number Now the whole number ratio comes out to be 3 96 which
can be approximated as 4
So, the empirical formula of compound
is Pb3â€‹O4
Regardsâ€‹

Element	AtomicMass	Percentage	Relative Number of Moles	Simplest mole of Ratio	Whole Number ratio
Pb(Lead)	207	90.66%	90.66/207=0.44	0.44/0.44=1	1X3=3
O(oxygen)	16	9.34%	9.34/16=0.58	0.58/0.44=1.318	1.32X3=3.96

Please anyone solve it and explain..

Since, the mole ratio of oxygen is fractional so, we multiply the whole ratio by 3 to make it a whole number.Now the whole number ratio comes out to be 3.96 which can be approximated as 4
So, the empirical formula of compound is Pb₃O_{4
Regards}

Please anyone solve it and explain..

Since, the mole ratio of oxygen is fractional so, we multiply the whole ratio by 3 to make it a whole number.Now the whole number ratio comes out to be 3.96 which can be approximated as 4 So, the empirical formula of compound is Pb3​O4 Regards​

Since, the mole ratio of oxygen is fractional so, we multiply the whole ratio by 3 to make it a whole number.Now the whole number ratio comes out to be 3.96 which can be approximated as 4
So, the empirical formula of compound is Pb₃O_{4
Regards}