please check that the following match the following is correctly answered or not
Dear student,
1.when NaOH is added to solution containing Cu2+ blue precipitate is observed due to the formation of copper hydroxide Cu(OH)2
Cu2+ + 2NaOH → Cu(OH)2 + 2Na+
2. When Sodium Hydroxide is added a to the solution containing Fe2+ ion a dirty-green precipitate is observed due to the formation Ferrous hydroxide.
Fe2+ + 2NaOH → Fe(OH)2 + 2Na+
3. Sodium hydroxide precipitates lead(II) hydroxide, which is white in colour and dissolve with excess hydroxide.
Pb2+ + 2 NaOH → Pb(OH)2 + 2Na+
4. When sodium hydroxide is added to Fe(III) ions reddish brown precipitate is observed due to the formation of ferric hydroxide.
Fe3+ + 3NaOH → Fe(OH)3 + 3Na+
5. When sodium hydroxide is added to solution containing Ca2+ ions a chalky white ppt. is observed which is insoluble in excess of sodium hydroxide.
Ca2+ + 2NaOH → Can(OH)2 + 2Na+
All your answers are correct.
Regards
1.when NaOH is added to solution containing Cu2+ blue precipitate is observed due to the formation of copper hydroxide Cu(OH)2
Cu2+ + 2NaOH → Cu(OH)2 + 2Na+
2. When Sodium Hydroxide is added a to the solution containing Fe2+ ion a dirty-green precipitate is observed due to the formation Ferrous hydroxide.
Fe2+ + 2NaOH → Fe(OH)2 + 2Na+
3. Sodium hydroxide precipitates lead(II) hydroxide, which is white in colour and dissolve with excess hydroxide.
Pb2+ + 2 NaOH → Pb(OH)2 + 2Na+
4. When sodium hydroxide is added to Fe(III) ions reddish brown precipitate is observed due to the formation of ferric hydroxide.
Fe3+ + 3NaOH → Fe(OH)3 + 3Na+
5. When sodium hydroxide is added to solution containing Ca2+ ions a chalky white ppt. is observed which is insoluble in excess of sodium hydroxide.
Ca2+ + 2NaOH → Can(OH)2 + 2Na+
All your answers are correct.
Regards