Please clarify this doubt :
QUESTION :
FIND THE POINT ON THE X AXIS WHICH IS EQUIDISTANT FROM ( 2,-5) AND ( -2, 9 )
DOUBT :
THIS PROBLEM WHEN SOLVED CONSIDERING THE TWO PINTS GIVEN GIVEN AS P AND Q AND THE MID POINT AS R , WE GET PR = QR AND WE GET RESULT AS R = ( -7, 0 )
WHY DOES THE SECTION FORMULA REDUCED TO EQUIDISTANT FORMULA ( X1 + X2 )/ 2 SINCE M1 = M2 DOES NOT GIVE SAME ANSWER .
SO IS THE EQUIDISTANT FORMULA NOT VALID TO BE USED WHEN THE INTERSECTION IN ON THE AXIS ( X AXIS OR Y AXIS ).
THE SAME EQUIDISTANT FORMULA WORKS IN OTHER CASES, FOR EXAMPLE IN THE BELO W QUSETION ( TRISECTION ).
FIND THE COORDINATES OF THE POINTS OF TRISECTION OF THE LINE SEGMENT JOINING POINTS A( 2,-2), B(-7,4 ).
PLEASE CLARIFY IMMEDIATELY.
THANKS
FIND THE POINT ON THE X AXIS WHICH IS EQUIDISTANT FROM ( 2,-5) AND ( -2, 9 )
Solution:
Let (x ,0) be the point on x-axis which is equidistant from (2, - 5) and (- 2, 9)
therefore, by using distance formula,
Thus, (-7, 0) be the point on x-axis which is equidistant from (2, -5) and (-2, 9).