Dear Student, We have,x2+3x+5<x2+x+1Squaring both sides, we get;x2+3x+5<x2+x+12x<-4x<-2therefore, x∈-∞,-2 Regards

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Dear Student,

W e h a v e, \sqrt{x^{2} + 3 x + 5} < \sqrt{x^{2} + x + 1} S q u a r i n g b o t h s i d e s, w e g e t; x^{2} + 3 x + 5 < x^{2} + x + 1 2 x < - 4 x < - 2 t h e r e f o r e, x \in (- \infty, - 2)

Regards.

Aakash EduTech Pvt. Ltd.

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