PLEASE DO NOT SEND ANY LINKS. Solve to the 21st question. PLEASE DO NOT SEND ANY LINKS. Solve to the 21st question. 7 Share with your friends Share 0 Varun Rawat answered this Let the sum invested at 12% simple interest = Rs xLet the sum invested at 10% simple interest = Rs yCASE 1 :Principal, P1 = Rs xRate, R1 = 12% p.aTime, T = 1 yrI1 = P1 × R1 × T100 =x×12×1100 = Rs3x25Principal, P2 = Rs yRate, R2 = 10% p.aTime, T = 1 yrI2 = P2 × R2 × T100 =y×10×1100 = Rsy10Now, according to question :3x25 + y10 = 1300⇒6x + 5y50 = 1300⇒6x + 5y = 65000 .....1CASE 2 :Principal, P1 = Rs xRate, R1 = 10% p.aTime, T = 1 yrI1 = P1 × R1 × T100 =x×10×1100 = Rsx10Principal, P2 = Rs yRate, R2 = 12% p.aTime, T = 1 yrI2 = P2 × R2 × T100 =x×12×1100 = Rs3y25Now, according to question : x10 + 3y25 = 1340⇒5x + 6y50 = 1340⇒5x + 6y = 67000 .....2Adding 1 and 2, we get11x + 11y = 132000 ⇒ x + y = 12000 ......3Subtracting 2 from 1, we getx - y = -2000 .....4Adding 3 and 4, we get2x = 10000 ⇒x = 5000Now, from 3, we gety = 7000So, amount invested at 12% SI is Rs 5000 and 10% SI is Rs 7000. 0 View Full Answer Pranav answered this easy bro 1
