Please do this...

Dear Student,

We can calculate it from the formulae given below :
n space equals space 360 to the power of 0 over theta space minus space 1 comma space i f space 360 over theta space i s space e v e n space i n t e g e r a n d space n space equals space 360 over theta space i s space a n space o d d space i n t e g e r w h e r e comma space theta space i s space t h e space a n g l e space b e t w e e n space t w o space p l a n e space m i r r o r s a n d space n space i s space t h e space t o t a l space n o. space o f space i m a g e s space f o r m e d.

​​​​​​​a- 360o30o=12(even)So number of images = 12-1=11b- 360o60o=6(even)So number of images = 6=5c- 360o45o=8(even)So number of images = 8-1=7d-360o90o=4(even)So number of images = 4-1=3So images will be maximum in case a.Regards

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45? is correct
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Sorry 45 degree
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