PLEASE EXPLAIN 58TH QUES

Dear Student,

S + O_{2} \to {SO}_{2} ∆ H_{i} = - 298.2 {kJmole}^{- 1} . . . (i) {SO}_{2} + \frac{1}{2} O_{2} \to {SO}_{3} ∆ H_{ii} = - 98.7 {kJmole}^{- 1} . . . (ii) {SO}_{3} + H_{2} O \to H_{2} {SO}_{4} ∆ H_{iii} = - 130.2 {kJmole}^{- 1} . . . (iii) H_{2} + \frac{1}{2} O_{2} \to H_{2} O ∆ H_{iv} = - 287.3 {kJmole}^{- 1} . . . (iv) We need to find enthapy of formation of H_{2} {SO}_{4} i . e . H_{2} + S + 2 O_{2} \to H_{2} {SO}_{4} ∆ H = ? . . (v) (v) can be obtained by adding (i), (ii), (iii) and (iv) ∆ H = ∆ H_{i} + ∆ H_{ii} + ∆ H_{iii} + ∆ H_{iv} = (- 298.2) + (- 98.7) + (- 130.2) + (- 287.3) = - 814.4 {kJmole}^{- 1} Hence, the correct answer is (A)

​​PLEASE EXPLAIN 58TH QUES