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Please explain how to find the answer of the following question

10.  Excess of silver nitrate solution is added to 100 mL of  0.01 M pentaaquachlorochromium (III) chloride         solution.  The mass of silver chloride obtained ( in gram ) is [Atomic mass of silver is 108]
                                                                                                                                                  [KCET 2011]
(a)  287 x 10-3                                                              (c)  143.5 x 10-3
(b)  143.5 x 10-2                                                           (d)  287 x 10-2

Dear student
Please find the solution to the asked query:

No.of moles of the complex =M(moles/litre) x V(litre) =0.01×100/1000 =0.001[Cr(H2O)5Cl]Cl2 has two ionizable Cl- ionsSo,0.001 x 2=0.002 moles would precipitate two Cl ionsMass of silver chloride obtained = 108 x 0.002 =.216 =216 x 10-3which is very close to option (A)

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