Please explain how to solve the 27th one:

$27 . CFSE (∆_{0}) for metal ion in d^{7} configuration in presence of strong ligand field is (1) - 0.3 ∆_{0} (2) - 0.8 ∆_{0} (3) - 1.6 ∆_{0} (4) - 1.8 ∆_{0}$

Question

Please explain how to solve the 27th one:

27   CFSE ∆ 0   for   metal   ion  
in   d 7   configuration   in   presence  
of   strong   ligand   field   is 1   - 0
3   ∆ 0              
        2   - 0 8   ∆ 0  
3   - 1 6   ∆ 0          
          4   - 1 8   ∆ 0

Ravjot Kaur · Accepted Answer

Dear student

A strong ligand produces a low spin complex
So d7 low spin configuration will be:

<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ck_59d8855bf3330%20png"
style="width: 178px; height: 250px;">
CFSE =-0 4 x 6 + 0 6x 1
=-2 4 +0 6
=-1 8Δo
Hence option (4) is correct

Regards

Please explain how to solve the 27th one: 27 . CFSE ∆ 0 for metal ion in d 7 configuration in presence of strong ligand field is 1 - 0 . 3 ∆ 0 2 - 0 . 8 ∆ 0 3 - 1 . 6 ∆ 0 4 - 1 . 8 ∆ 0

Please explain how to solve the 27th one:

$27 . CFSE (∆_{0}) for metal ion in d^{7} configuration in presence of strong ligand field is (1) - 0.3 ∆_{0} (2) - 0.8 ∆_{0} (3) - 1.6 ∆_{0} (4) - 1.8 ∆_{0}$