Please explain in detail.Please explain in detail. ONLY CNE OPTION CORRECT : = "001%. , 6} cute 0'001'/. htt.bv() (A) 21v' .totu 5W (D) tow 2, A cvabblc Share with your friends Share 0 Shobhit Mittal answered this Dear Student, stopping potential =5 V total energy of photon =2eV+5eV=7eVphoto satuaration current =10 micro ampere no of electron emitted per second=10-5/1.6*10-19=6.25 *1013 electronno of photon emitted by light per second=6.25 *1013/10-5=6.25 *1018 photon per secondenergy per second that is power =6.25 *1018*7*1.6*10-19=7 wattoption C is correct.regards 1 View Full Answer