Please explain no 23 Answer is (2) In a R-L circuit discharging curent is given by I=I0e-t/τ, where τ - Physics - Alternating Current

Question

Please explain no 23 Answer is (2)
I n   a   R - L   c i r c u i t   d i s c h a r
g i n g   c u r e n t   i s   g i v e n   b y
  I = I 0 e - t / τ ,   w h e r e   τ  
i s   t h e   t i m e   c o n s tan t   o f
  t h e   c i r c u i t   T h e   a v e r a g e
  c u r r e n t   f o r   t h e   p e r i o d
  t = 0   t o   t = τ   i s ( 1 )   2
I 0 e [ e - 1 ] ( 2 )   I 0 e [ e - 1 ] ( 3 )   2 I 0 e (
4 )   I 0 e

Decoder_2 · Accepted Answer

Dear Student,
average current for the period will be given by,Average current=∫0τIdτ∫0τdτ=∫0τI0e-t/τdττ=Io×(e-1)e=Ioe(e-1)
Regardsâ€‹