Please explain question 52.

 

The reaction between Sodium Chromate and  Sulphuric acid is given as:

 

2 Na₂CrO₄​ +  H₂​SO₄​ → Na₂Cr₂​O₇ + H_​​​2O +  Na₂​SO₄

 

CrO₄​^2- (chromate ion) is yellow in colour. When it is oxidized by H⁺ in Cr₂O₇^2-​(dichromate ion), the colour changes to orange.

 

Therefore, option (a) is correct.

 

 Regards