please explain the answer Share with your friends Share 0 Tanveer Sofi answered this In ∆ABC, we have,AB = AC given ⇒AB2 = AC2 ....1Now, AB = AC⇒∠C = ∠B Angles opposie to equal sides are equalSince, BD is a median to AC, thenAD = DC = AB2Since, CE is a median to AB, thenAE = EB = AB2Now, from 1, we getEB = DC .....2In ∆EBC and ∆DBC, we haveEB = DC using 2∠B = ∠C Proved aboveBC = BC Common∆EBC≅ ∆DBC SAS⇒CE = BD CPCT 7 View Full Answer
